w^2-w(w-3)=12(1+4)

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Solution for w^2-w(w-3)=12(1+4) equation: 



w^2-w(w-3)=12(1+4)

We move all terms to the left:

w^2-w(w-3)-(12(1+4))=0

We add all the numbers together, and all the variables

w^2-w(w-3)-(125)=0

We add all the numbers together, and all the variables

w^2-w(w-3)-125=0

We multiply parentheses

w^2-w^2+3w-125=0

We add all the numbers together, and all the variables

3w-125=0

We move all terms containing w to the left, all other terms to the right

3w=125

w=125/3

w=41+2/3

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